@ebarchuleta1 asked 6 months ago.

How much heat is required to warm 1.70 l of water from 30.0 ∘c to 100.0 ∘c?

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@BombayVelvet answered 6 months ago.

Using the formula Q = mCΔT, where Q is the heat required, m is the mass of water, C is the specific heat capacity of water, and ΔT is the change in temperature, we can solve for the amount of heat required to warm 1.70 liters of water from 30.0 to 100. The specific heat of water is 4186 J/(kg K). The amount of heat required to raise the temperature of 1.70 kg of water from 30.0 ∘C to 100.0 ∘C is therefore, Q = 4186 J/(kg K)(1.70 kg) = 12206000 J.

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