@dom answered 5 months ago.

How much heat is required to warm 1.50 kg of sand from 26.0 ?C to 100.0 ?C?? Step 1: Write the heat capacity equation. Q = mcΔT where Q is the heat input, m is the mass of the object, c is the heat capacity, and ΔT is the temperature difference.

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@trustissue answered 5 months ago.

How much heat is required to warm 1.50 kg of sand from 26.0 ?C to 100.0 ?C?? Step 1: Write the heat capacity equation. Q = mcΔT where Q is the heat input, m is the mass of the object, c is the heat capacity, and ΔT is the temperature difference.

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@zafammettete answered 7 months ago.

How much heat is required to warm 1.50 kg of sand from 26.0 ?C to 100.0 ?C?? Step 1: Write the heat capacity equation. Q = mcΔT where Q is the heat input, m is the mass of the object, c is the heat capacity, and ΔT is the temperature difference.

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@durraqammoss answered 8 months ago.

The heat required to warm 1.50 kg of sand from 26.0 ?c to 100.0 ?c is 333.64 joules. This heat is calculated by using the formula Q = mcT. In this case, Q is equal to 333.64.

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